What is the derivative of 4x^{5/4}+2x^{3/2}+7x ?

The derivative of 4x^{5/4}+2x^{3/2}+7x is 5x^{1/4}+3x^{1/2}+7

What is the first derivative of 4x^{5/4}+2x^{3/2}+7x ?

The first derivative of 4x^{5/4}+2x^{3/2}+7x is 5x^{1/4}+3x^{1/2}+7

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\frac{d}{d x} (4 x^{\frac{5}{4}} + 2 x^{\frac{3}{2}} + 7 x)

5 x^{\frac{1}{4}} + 3 x^{\frac{1}{2}} + 7

Solution steps

\frac{d}{d x} (4 x^{\frac{5}{4}} + 2 x^{\frac{3}{2}} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{5}{4}}) + \frac{d}{d x} (2 x^{\frac{3}{2}}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (4 x^{\frac{5}{4}}) = 5 x^{\frac{1}{4}}

\frac{d}{d x} (2 x^{\frac{3}{2}}) = 3 x^{\frac{1}{2}}

\frac{d}{d x} (7 x) = 7

= 5 x^{\frac{1}{4}} + 3 x^{\frac{1}{2}} + 7

e^{3 a - 2 b t}

\int \frac{4}{x ^{2} + 4 x + 8} d x

n = 1 \sum \infty \frac{3}{2 n + 3}

\int (5 e^{- 0.4 x}) d x

e^{- 2 x}

What is the derivative of 4x^{5/4}+2x^{3/2}+7x ?
The derivative of 4x^{5/4}+2x^{3/2}+7x is 5x^{1/4}+3x^{1/2}+7
What is the first derivative of 4x^{5/4}+2x^{3/2}+7x ?
The first derivative of 4x^{5/4}+2x^{3/2}+7x is 5x^{1/4}+3x^{1/2}+7