What is (\partial)/(\partial x)(-0.06x^2+1.08x) ?

The answer to (\partial)/(\partial x)(-0.06x^2+1.08x) is -0.12x+1.08

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(\partial)/(\partial x)(-0.06x^2+1.08x)

\frac{\partial}{\partial x} (- 0.06 x^{2} + 1.08 x)

- 0.12 x + 1.08

Solution steps

\frac{\partial}{\partial x} (- 0.06 x^{2} + 1.08 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (0.06 x^{2}) + \frac{\partial}{\partial x} (1.08 x)

\frac{\partial}{\partial x} (0.06 x^{2}) = 0.12 x

\frac{\partial}{\partial x} (1.08 x) = 1.08

= - 0.12 x + 1.08

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What is (\partial)/(\partial x)(-0.06x^2+1.08x) ?
The answer to (\partial)/(\partial x)(-0.06x^2+1.08x) is -0.12x+1.08