What is the sum from n=0 to infinity of 3-(0.5)^n ?

The sum from n=0 to infinity of 3-(0.5)^n is diverges

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sum from n=0 to infinity of 3-(0.5)^n

n = 0 \sum \infty 3 - (0.5)^{n}

diverges

Solution steps

n = 0 \sum \infty 3 - 0. 5^{n}

Apply Series Divergence Test:

diverges

= diverges

\int_{1}^{\infty} \frac{1}{x ^{6}} d x

\frac{1}{( 2 s + 4 )}

\int (4 x + 3)^{5} d x

\frac{d}{d x} (\frac{ln ( x )}{7})

f (x) = x^{3} - 3 x

What is the sum from n=0 to infinity of 3-(0.5)^n ?
The sum from n=0 to infinity of 3-(0.5)^n is diverges