What is the integral from 1 to infinity of sin^2(x) ?

The integral from 1 to infinity of sin^2(x) is diverges

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integral from 1 to infinity of sin^2(x)

\int_{1}^{\infty} sin^{2} (x) d x

diverges

Solution steps

\int_{1}^{\infty} sin^{2} (x) d x

Compute the indefinite integral:

\int sin^{2} (x) d x = \frac{1}{2} (x - \frac{1}{2} sin (2 x)) + C

Compute the boundaries:

\int_{1}^{\infty} sin^{2} (x) d x =

diverges

= diverges

\frac{d}{d x} (cot (x^{4}))

\frac{d}{d x} (\frac{x ^{2}}{2} - \frac{x ^{7}}{7})

(2 x y^{2} + y) d x + (2 x^{2} y + x) d y = 0

\int \frac{7 t - 5}{t + 1} d t

\int (x^{2} - 5 x + 9) d x

What is the integral from 1 to infinity of sin^2(x) ?
The integral from 1 to infinity of sin^2(x) is diverges