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Popular >

derivative of 2cos(2x)+2sin(2x)+4x

Solution

derivative of

2 cos (2 x) + 2 sin (2 x) + 4 x

Solution

- 4 sin (2 x) + 4 cos (2 x) + 4

Solution steps

\frac{d}{d x} (2 cos (2 x) + 2 sin (2 x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (2 x)) + \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (4 x) = 4

= - 4 sin (2 x) + 4 cos (2 x) + 4

Graph

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n = 0 \sum \infty \frac{n !}{( 2 n ) !}

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Frequently Asked Questions (FAQ)

What is the derivative of 2cos(2x)+2sin(2x)+4x ?
The derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4
What is the first derivative of 2cos(2x)+2sin(2x)+4x ?
The first derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4