What is the derivative of (ln(3)/x) ?

The derivative of (ln(3)/x) is -(ln(3))/(x^2)

What is the first derivative of (ln(3)/x) ?

The first derivative of (ln(3)/x) is -(ln(3))/(x^2)

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\frac{d}{d x} (\frac{ln ( 3 )}{x})

- \frac{ln ( 3 )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( 3 )}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (3) \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= ln (3) \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= ln (3) (- 1 \cdot x^{- 1 - 1})

Simplify

ln (3) (- 1 \cdot x^{- 1 - 1}) : - \frac{ln ( 3 )}{x ^{2}}

= - \frac{ln ( 3 )}{x ^{2}}

y^{^{''}} + 6 y^{^{'}} + 4 y = 0

\int_{0}^{\frac{π}{2}} 9 cos^{2} (x) d x

\int 8 x (4 x^{2} + 3)^{6} d x

\int_{0}^{1} \frac{1}{4 - x ^{2}} d x

h (t) = (\frac{t ^{3}}{t ^{8} + 3})^{2}

What is the derivative of (ln(3)/x) ?
The derivative of (ln(3)/x) is -(ln(3))/(x^2)
What is the first derivative of (ln(3)/x) ?
The first derivative of (ln(3)/x) is -(ln(3))/(x^2)