What is the tangent of f(x)=8e^xcos(x),(0,8) ?

The tangent of f(x)=8e^xcos(x),(0,8) is y=8x+8

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tangent of f(x)=8e^xcos(x),(0,8)

tangent of

f (x) = 8 e^{x} cos (x), (0, 8)

y = 8 x + 8

Solution steps

Find the slope of

f (x) = 8 e^{x} cos (x) : \frac{df ( x )}{d x} = 8 (e^{x} cos (x) - e^{x} sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(0, 8) : y = 8 x + 8

y = 8 x + 8

\frac{d}{d t} (\frac{t}{t ^{2} + y ^{2}})

x \to 5 lim (3 x^{2} + 5)

\frac{d}{d x} (\frac{2}{3} x^{2})

\frac{d}{d x} (\frac{c ^{6} - x ^{6}}{c ^{6} + x ^{6}})

n = 1 \sum \infty (\frac{1}{n + 1})^{2}

What is the tangent of f(x)=8e^xcos(x),(0,8) ?
The tangent of f(x)=8e^xcos(x),(0,8) is y=8x+8