What is the tangent of y=x^2,(0,-9) ?

The tangent of y=x^2,(0,-9) is y=6x-9 \lor y=-6x-9

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tangent of y=x^2,(0,-9)

tangent of

y = x^{2}, (0, - 9)

y = 6 x - 9 or y = - 6 x - 9

Solution steps

Slope of the tangent line at

(0, - 9) : m = \frac{x ^{2} + 9}{x}

Find the slope of

y = x^{2} : m = 2 x

Solve

2 x = \frac{x ^{2} + 9}{x} : x = 3, x = - 3

Find the tangent line at

x = 3 : y = 6 x - 9

Find the tangent line at

x = - 3 : y = - 6 x - 9

y = 6 x - 9 or y = - 6 x - 9

\int tan (x) sec (2 x) d x

\int x (x - 10)^{7} d x

y = x^{2} + x, (2, 6)

\frac{( x - cos ( x ) )}{x ^{2} + cot ( x )}

x \to 2 - lim (0)

What is the tangent of y=x^2,(0,-9) ?
The tangent of y=x^2,(0,-9) is y=6x-9 \lor y=-6x-9