What is the sum from n=1 to infinity of (5/6)^nn ?

The sum from n=1 to infinity of (5/6)^nn is converges

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sum from n=1 to infinity of (5/6)^nn

n = 1 \sum \infty (\frac{5}{6})^{n} n

converges

Solution steps

n = 1 \sum \infty (\frac{5}{6})^{n} n

Apply Series Ratio Test:

converges

= converges

\int 2 \frac{sin ( 2 x )}{sin ( x )} d x

\int (4 x - 3) d x

e^{x}, x = 2

y = \frac{4 81 + x - 3}{x}

y^{^{'}} + 8 y + 6 x = 0

What is the sum from n=1 to infinity of (5/6)^nn ?
The sum from n=1 to infinity of (5/6)^nn is converges