What is the derivative of f(x)=533.33+(x/(250))^2 ?

The derivative of f(x)=533.33+(x/(250))^2 is 0.000032x

What is the first derivative of f(x)=533.33+(x/(250))^2 ?

The first derivative of f(x)=533.33+(x/(250))^2 is 0.000032x

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derivative of

f (x) = 533.33 + (\frac{x}{250})^{2}

0.000032 x

Solution steps

\frac{d}{d x} (533.33 + (\frac{x}{250})^{2})

Simplify

533.33 + (\frac{x}{250})^{2} : 533.33 + 0.000016 x^{2}

= \frac{d}{d x} (533.33 + 0.000016 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (533.33) + \frac{d}{d x} (0.000016 x^{2})

\frac{d}{d x} (533.33) = 0

\frac{d}{d x} (0.000016 x^{2}) = 0.000032 x

= 0 + 0.000032 x

Simplify

= 0.000032 x

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What is the derivative of f(x)=533.33+(x/(250))^2 ?
The derivative of f(x)=533.33+(x/(250))^2 is 0.000032x
What is the first derivative of f(x)=533.33+(x/(250))^2 ?
The first derivative of f(x)=533.33+(x/(250))^2 is 0.000032x