What is the integral from-2 to-1 of (4y^3+2/(y^3)) ?

The integral from-2 to-1 of (4y^3+2/(y^3)) is -63/4

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integral from-2 to-1 of (4y^3+2/(y^3))

\int_{- 2}^{- 1} (4 y^{3} + \frac{2}{y ^{3}}) d y

- \frac{63}{4}

Decimal

- 15.75

Solution steps

\int_{- 2}^{- 1} 4 y^{3} + \frac{2}{y ^{3}} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} 4 y^{3} d y + \int_{- 2}^{- 1} \frac{2}{y ^{3}} d y

\int_{- 2}^{- 1} 4 y^{3} d y = - 15

\int_{- 2}^{- 1} \frac{2}{y ^{3}} d y = - \frac{3}{4}

= - 15 - \frac{3}{4}

Simplify

- 15 - \frac{3}{4} : - \frac{63}{4}

= - \frac{63}{4}

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What is the integral from-2 to-1 of (4y^3+2/(y^3)) ?
The integral from-2 to-1 of (4y^3+2/(y^3)) is -63/4