What is (\partial)/(\partial x)(9x^{2y}) ?

The answer to (\partial)/(\partial x)(9x^{2y}) is 18yx^{2y-1}

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(\partial)/(\partial x)(9x^{2y})

\frac{\partial}{\partial x} (9 x^{2 y})

18 y x^{2 y - 1}

Solution steps

\frac{\partial}{\partial x} (9 x^{2 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{\partial}{\partial x} (x^{2 y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 2 y x^{2 y - 1}

Simplify

= 18 y x^{2 y - 1}

x^{4} + 9 x^{2} - x

4 x^{2} y^{^{''}} + 4 x y^{^{'}} - y = 0

\int x cos^{3} (x) d x

\frac{x ^{3}}{3} + 2 x^{2} + 4 x - 1

x \to 0 lim (6 sin (x) - 1)

What is (\partial)/(\partial x)(9x^{2y}) ?
The answer to (\partial)/(\partial x)(9x^{2y}) is 18yx^{2y-1}