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Popular >

integral of 10-t

Solution

\int 10 - t d t

Solution

10 t - \frac{t ^{2}}{2} + C

Solution steps

\int 10 - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 d t - \int t d t

\int 10 d t = 10 t

\int t d t = \frac{t ^{2}}{2}

= 10 t - \frac{t ^{2}}{2}

Add a constant to the solution

= 10 t - \frac{t ^{2}}{2} + C

Graph

Popular Examples

derivative of y=x^{-2}derivative of

y = x^{- 2}

inverse oflaplace (s+1)/(s^2(s-1))inverse laplace

\frac{s + 1}{s ^{2} ( s - 1 )}

derivative of (x^2/8)

\frac{d}{d x} (\frac{x ^{2}}{8})

y^{''}+8y^'+12y=0

y^{^{''}} + 8 y^{^{'}} + 12 y = 0

inverse oflaplace (0.5)/((s^2+s+1))*1/s inverse laplace

\frac{0.5}{( s ^{2} + s + 1 )} \cdot \frac{1}{s}

Frequently Asked Questions (FAQ)

What is the integral of 10-t ?
The integral of 10-t is 10t-(t^2)/2+C