What is the derivative of (800t)/(t+2) ?

The derivative of (800t)/(t+2) is (1600)/((t+2)^2)

What is the first derivative of (800t)/(t+2) ?

The first derivative of (800t)/(t+2) is (1600)/((t+2)^2)

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derivative of

\frac{800 t}{t + 2}

\frac{1600}{( t + 2 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{800 t}{t + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 800 \frac{d}{d t} (\frac{t}{t + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 800 \cdot \frac{\frac{d t}{d t} ( t + 2 ) - \frac{d}{d t} ( t + 2 ) t}{( t + 2 ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} (t + 2) = 1

= 800 \cdot \frac{1 \cdot ( t + 2 ) - 1 \cdot t}{( t + 2 ) ^{2}}

Simplify

800 \cdot \frac{1 \cdot ( t + 2 ) - 1 \cdot t}{( t + 2 ) ^{2}} : \frac{1600}{( t + 2 ) ^{2}}

= \frac{1600}{( t + 2 ) ^{2}}

n = 1 \sum \infty 2^{- n}

- 16 cos (4 t)

(3 x^{2} - 3 x) e^{x}

\frac{d}{d x} (\frac{1}{x ( 1 + ln ( x ) ) ^{2}})

n \to \infty lim ({3})

What is the derivative of (800t)/(t+2) ?
The derivative of (800t)/(t+2) is (1600)/((t+2)^2)
What is the first derivative of (800t)/(t+2) ?
The first derivative of (800t)/(t+2) is (1600)/((t+2)^2)