What is the d/(dt)(10cos(t)) ?

The d/(dt)(10cos(t)) is -10sin(t)

What is the first d/(dt)(10cos(t)) ?

The first d/(dt)(10cos(t)) is -10sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (10 cos (t))

- 10 sin (t)

Solution steps

\frac{d}{d t} (10 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 10 (- sin (t))

Simplify

= - 10 sin (t)

\int 4 - (x - 2)^{2} d x

\frac{d}{d x} (\frac{x ^{\frac{3}{2}}}{3})

\int_{0}^{1} (1 - x^{3})^{2} d x

g (x) = ln (2 x^{2} + 4)

(6 t - 1) (4 t - 4)^{- 1}