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Popular >

y^'=9y^2+xy^2

Solution

y^{^{'}} = 9 y^{2} + x y^{2}

Solution

y = - \frac{2}{18 x + x ^{2} + c _{1}}

Solution steps

y^{'} (x) = 9 y^{2} + x y^{2}

Solve separable ODE:

y = - \frac{2}{18 x + x ^{2} + c _{1}}

y = - \frac{2}{18 x + x ^{2} + c _{1}}

Popular Examples

derivative of (2x/(sqrt(x)-1))

\frac{d}{d x} (\frac{2 x}{x - 1})

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y = e^{4} x^{2} + 18

derivative of f(x)=((8x+7)/(9x^2+6))derivative of

f (x) = (\frac{8 x + 7}{9 x ^{2} + 6})

area y=cos(x),y=sin(x)area

y = cos (x), y = sin (x)

area 7e^x,7xe^{x^2},[0,1]area

7 e^{x}, 7 x e^{x^{2}}, [0, 1]

Frequently Asked Questions (FAQ)

What is the solution for y^'=9y^2+xy^2 ?
The solution for y^'=9y^2+xy^2 is y=-2/(18x+x^2+c_{1)}