What is (\partial)/(\partial y)(4xy^2) ?

The answer to (\partial)/(\partial y)(4xy^2) is 8xy

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(\partial)/(\partial y)(4xy^2)

\frac{\partial}{\partial y} (4 x y^{2})

8 x y

Solution steps

\frac{\partial}{\partial y} (4 x y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 x \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 x \cdot 2 y^{2 - 1}

Simplify

= 8 x y

x \to \infty lim (\frac{2}{x})

- 6 t^{2} y^{^{''}} + 3 t (t + 4) y^{^{'}} - 3 (t + 4) y = 4 t^{3}

\frac{d y}{d x} + e^{x} y^{2} = x^{2} y^{2}

\frac{d}{d x} (4 sec (7 x))

\frac{d}{d x} (22 - x)

What is (\partial)/(\partial y)(4xy^2) ?
The answer to (\partial)/(\partial y)(4xy^2) is 8xy