What is the sum from n=0 to infinity of 5/(n+2) ?

The sum from n=0 to infinity of 5/(n+2) is diverges

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sum from n=0 to infinity of 5/(n+2)

n = 0 \sum \infty \frac{5}{n + 2}

diverges

Solution steps

n = 0 \sum \infty \frac{5}{n + 2}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty \frac{1}{n + 2}

Apply Series Integral Test:

diverges

= 5 diverges

= diverges

y = x^{4}

33.62 x^{^{'}} + x = 100

7 e^{- x^{2}}

y^{^{''}} + 4 y^{^{'}} + 5 y = - 5 x + e^{- x}

y = \frac{x ^{2}}{( x + 2 )}

What is the sum from n=0 to infinity of 5/(n+2) ?
The sum from n=0 to infinity of 5/(n+2) is diverges