What is the integral of (\sqrt[3]{x^5}) ?

The integral of (\sqrt[3]{x^5}) is 3/8 x^{8/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (\sqrt[3]{x^5})

\frac{3}{8} x^{\frac{8}{3}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{5}{3}} d x

Apply the Power Rule

: \frac{3}{8} x^{\frac{8}{3}}

= \frac{3}{8} x^{\frac{8}{3}}

Add a constant to the solution

= \frac{3}{8} x^{\frac{8}{3}} + C

\int \frac{x + 1}{x ^{2} + 1} d x

\frac{d}{d x} (8 cosh (\frac{x}{4}) ln (arcsin (x)))

\frac{d ^{2}}{d x ^{2}} (2 x^{- 7})

x \to 9 lim (5 x + ∣ x - 9 ∣)

\frac{d}{d x} (\frac{4 - x ^{2}}{4})

What is the integral of (\sqrt[3]{x^5}) ?
The integral of (\sqrt[3]{x^5}) is 3/8 x^{8/3}+C