What is the solution for 9x^2y^2+x^{3/2}(dy)/(dx)=y^2 ?

The solution for 9x^2y^2+x^{3/2}(dy)/(dx)=y^2 is y=-(x^{1/2})/(-2-6x^2+c_{1)x^{1/2}}

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9x^2y^2+x^{3/2}(dy)/(dx)=y^2

9 x^{2} y^{2} + x^{\frac{3}{2}} \frac{d y}{d x} = y^{2}

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

Solution steps

9 x^{2} y^{2} + x^{\frac{3}{2}} \frac{d y}{d x} = y^{2}

Solve separable ODE:

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

y = - \frac{x ^{\frac{1}{2}}}{- 2 - 6 x ^{2} + c _{1} x ^{\frac{1}{2}}}

\frac{x}{x ^{- 1} + 7}

\int \frac{w ^{3}}{w + 1} d w

\frac{d}{d x} (19 arctan (x))

ln (\frac{6 x ^{2} + 5}{x ^{\frac{4}{5}}})

\frac{s + 4}{s ^{2} + 2 s - 3}

What is the solution for 9x^2y^2+x^{3/2}(dy)/(dx)=y^2 ?
The solution for 9x^2y^2+x^{3/2}(dy)/(dx)=y^2 is y=-(x^{1/2})/(-2-6x^2+c_{1)x^{1/2}}