What is the solution for y^{''}-2/x y^'-(10)/(x^2)y=0 ?

The solution for y^{''}-2/x y^'-(10)/(x^2)y=0 is y=c_{1}x^5+(c_{2})/(x^2)

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y^{''}-2/x y^'-(10)/(x^2)y=0

y^{^{''}} - \frac{2}{x} y^{^{'}} - \frac{10}{x ^{2}} y = 0

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

Solution steps

y^{''} (x) - \frac{2}{x} y^{'} (x) - \frac{10}{x ^{2}} y = 0

Solve linear ODE:

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

y = c_{1} x^{5} + \frac{c _{2}}{x ^{2}}

cos (4 x)

3 x + 4, at x = 4

\frac{d}{d x} (\frac{5 x}{( x ^{2} + 2 ) ^{2}})

f (x) = e^{x} x + 2 e^{x}

\int \frac{1}{x x ^{2} - 12} d x

What is the solution for y^{''}-2/x y^'-(10)/(x^2)y=0 ?
The solution for y^{''}-2/x y^'-(10)/(x^2)y=0 is y=c_{1}x^5+(c_{2})/(x^2)