What is the integral from 1 to 3 of (2.25)/(x^3) ?

The integral from 1 to 3 of (2.25)/(x^3) is 1

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integral from 1 to 3 of (2.25)/(x^3)

\int_{1}^{3} \frac{2.25}{x ^{3}} d x

1

Solution steps

\int_{1}^{3} \frac{2.25}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2.25 \cdot \int_{1}^{3} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{3}

= 2.25 [- \frac{1}{2 x ^{2}}]_{1}^{3}

Simplify

= 2.25 [- \frac{0.5}{x ^{2}}]_{1}^{3}

Compute the boundaries:

0.44444 \dots

= 2.25 \cdot 0.44444 \dots

Simplify

= 1

\frac{- 3 x ^{6} - x ^{5} + 3 x ^{4}}{x ^{2}}

n = 1 \sum \infty (- \frac{1}{2})^{n - 1}

\frac{d}{d x} (- \frac{5}{2} x^{9})

\int_{0}^{x} ln (x) d x

\frac{d ^{2}}{d x ^{2}} (x^{3} + 3 x^{2} - 2 x + 8)

What is the integral from 1 to 3 of (2.25)/(x^3) ?
The integral from 1 to 3 of (2.25)/(x^3) is 1