What is the solution for y^'=((1-y)^5)/4 ?

The solution for y^'=((1-y)^5)/4 is y=\sqrt[4]{1/(t+c_{1)}}+1,y=-\sqrt[4]{1/(t+c_{1)}}+1

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y^'=((1-y)^5)/4

y^{^{'}} = \frac{( 1 - y ) ^{5}}{4}

Solution steps

y^{'} (t) = \frac{( 1 - y ) ^{5}}{4}

Solve separable ODE:

y = 2 x e^{- x} + 2 e^{x^{5}}

\int x^{5} - sec (x) + \frac{1}{2 x} d x

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\int e^{x} - sin (x) d x

What is the solution for y^'=((1-y)^5)/4 ?
The solution for y^'=((1-y)^5)/4 is y=\sqrt[4]{1/(t+c_{1)}}+1,y=-\sqrt[4]{1/(t+c_{1)}}+1