What is the derivative of (x^2+x^4) ?

The derivative of (x^2+x^4) is 4(x^2+x)^3(2x+1)

What is the first derivative of (x^2+x^4) ?

The first derivative of (x^2+x^4) is 4(x^2+x)^3(2x+1)

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\frac{d}{d x} ((x^{2} + x)^{4})

4 (x^{2} + x)^{3} (2 x + 1)

Solution steps

\frac{d}{d x} ((x^{2} + x)^{4})

Apply the chain rule:

4 (x^{2} + x)^{3} \frac{d}{d x} (x^{2} + x)

= 4 (x^{2} + x)^{3} \frac{d}{d x} (x^{2} + x)

\frac{d}{d x} (x^{2} + x) = 2 x + 1

= 4 (x^{2} + x)^{3} (2 x + 1)

y = 4 x^{3} - 10 x^{2}

y^{^{''}} + 4 y = t e^{t}

x \to 2 - lim (\frac{4 x + 1}{x - 2})

\int x^{2} arccos (x) d x

\int 6 sin^{6} (x) cos^{3} (x) d x

What is the derivative of (x^2+x^4) ?
The derivative of (x^2+x^4) is 4(x^2+x)^3(2x+1)
What is the first derivative of (x^2+x^4) ?
The first derivative of (x^2+x^4) is 4(x^2+x)^3(2x+1)