What is the derivative of f(x)= 1/x-1 ?

The derivative of f(x)= 1/x-1 is -1/(x^2)

What is the first derivative of f(x)= 1/x-1 ?

The first derivative of f(x)= 1/x-1 is -1/(x^2)

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derivative of

f (x) = \frac{1}{x} - 1

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (1) = 0

= - \frac{1}{x ^{2}} - 0

Simplify

= - \frac{1}{x ^{2}}

\int 15 tan^{3} (θ) d θ

x^{2} \frac{d y}{d x} + x y = 5

\int_{- 8}^{0} (1 + 64 - x^{2}) d x

f (x) = 1 + x^{3}

n = 0 \sum \infty n^{n}

What is the derivative of f(x)= 1/x-1 ?
The derivative of f(x)= 1/x-1 is -1/(x^2)
What is the first derivative of f(x)= 1/x-1 ?
The first derivative of f(x)= 1/x-1 is -1/(x^2)