What is the integral from-infinity to 0 of 1/(5-7x) ?

The integral from-infinity to 0 of 1/(5-7x) is diverges

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integral from-infinity to 0 of 1/(5-7x)

\int_{- \infty}^{0} \frac{1}{5 - 7 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{5 - 7 x} d x

Compute the indefinite integral:

\int \frac{1}{5 - 7 x} d x = - \frac{1}{7} ln ∣ 5 - 7 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{5 - 7 x} d x =

diverges

= diverges

h (x) = \frac{x}{x ^{3} + 1}

f (x) = x (4 x - 12)^{3}

\frac{d}{d x} (\frac{e ^{4 x}}{x ^{12}})

f (x) = 4 x^{5} - x^{3} - 2

x \to + 0 - lim (\frac{e ^{x}}{x ^{3}})

What is the integral from-infinity to 0 of 1/(5-7x) ?
The integral from-infinity to 0 of 1/(5-7x) is diverges