What is the integral of sec(2x)*tan(2x) ?

The integral of sec(2x)*tan(2x) is 1/2 cos(2x)+1/2 sin(2x)tan(2x)+C

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integral of sec(2x)*tan(2x)

\int sec (2 x) \cdot tan (2 x) d x

\frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x) + C

Solution steps

\int sec (2 x) tan (2 x) d x

Rewrite using trig identities

= \int \frac{sin ( 2 x )}{cos ^{2} ( 2 x )} d x

Apply Integration By Parts

: - \int sin (2 x) d x + \frac{1}{2} sin (2 x) tan (2 x)

= - \int sin (2 x) d x + \frac{1}{2} sin (2 x) tan (2 x)

\int sin (2 x) d x = - \frac{1}{2} cos (2 x)

= - (- \frac{1}{2} cos (2 x)) + \frac{1}{2} sin (2 x) tan (2 x)

Simplify

= \frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x)

Add a constant to the solution

= \frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x) + C

\int \frac{2 x - 3}{x ^{2} + 4} d x

n = 1 \sum \infty \frac{2 n}{n ^{2}}

f (x) = 7 arctan (7 x)

y = - 8 x ln (6 x + 5)

\int_{0}^{1} (x + 3) (x - 4) d x

What is the integral of sec(2x)*tan(2x) ?
The integral of sec(2x)*tan(2x) is 1/2 cos(2x)+1/2 sin(2x)tan(2x)+C