What is the derivative of 1/(4+x) ?

The derivative of 1/(4+x) is -1/((4+x)^2)

What is the first derivative of 1/(4+x) ?

The first derivative of 1/(4+x) is -1/((4+x)^2)

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\frac{d}{d x} (\frac{1}{4 + x})

- \frac{1}{( 4 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{4 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((4 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 + x ) ^{2}} \frac{d}{d x} (4 + x)

= - \frac{1}{( 4 + x ) ^{2}} \frac{d}{d x} (4 + x)

\frac{d}{d x} (4 + x) = 1

= - \frac{1}{( 4 + x ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( 4 + x ) ^{2}}

\frac{d}{d x} ((4 x - 9) ln ((2 x - 5) (x - 2)))

\int_{2}^{1} (\frac{2}{x ^{2}} - 3 x^{2}) d x

\int 10 (x - 6)^{4} d x

\int \frac{1}{x ^{2} - x - 2} d x

2 y^{^{''}} + 8 y^{^{'}} = 0

What is the derivative of 1/(4+x) ?
The derivative of 1/(4+x) is -1/((4+x)^2)
What is the first derivative of 1/(4+x) ?
The first derivative of 1/(4+x) is -1/((4+x)^2)