What is the sum from n=0 to infinity of 1/(2^n+1) ?

The sum from n=0 to infinity of 1/(2^n+1) is converges

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sum from n=0 to infinity of 1/(2^n+1)

n = 0 \sum \infty \frac{1}{2 ^{n} + 1}

converges

Solution steps

n = 0 \sum \infty \frac{1}{2 ^{n} + 1}

Apply Series Ratio Test:

converges

= converges

f (x) = \frac{7 x}{x - 1}, at x = 2

\int_{0}^{6} π (- x^{2} + 6 x)^{2} d x

\int x + 3 x^{2} d x

\int - \frac{x + 37}{4} d x

2 x y \frac{d y}{d x} = 4 x^{2} + 3 y^{2}

What is the sum from n=0 to infinity of 1/(2^n+1) ?
The sum from n=0 to infinity of 1/(2^n+1) is converges