What is the derivative of 2x^2sin(x) ?

The derivative of 2x^2sin(x) is 2(2xsin(x)+cos(x)x^2)

What is the first derivative of 2x^2sin(x) ?

The first derivative of 2x^2sin(x) is 2(2xsin(x)+cos(x)x^2)

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\frac{d}{d x} (2 x^{2} sin (x))

2 (2 x sin (x) + cos (x) x^{2})

Solution steps

\frac{d}{d x} (2 x^{2} sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2} sin (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (x)

= 2 (\frac{d}{d x} (x^{2}) sin (x) + \frac{d}{d x} (sin (x)) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x)) = cos (x)

= 2 (2 x sin (x) + cos (x) x^{2})

- 8 e^{- 4 x^{2}} x

\frac{d}{d x} (x - a)

\int - tan (\frac{1}{2} x) d x

\int 4 x^{3} e^{5 x^{4}} d x

f (x) = 2 x^{2} (x - 3)

What is the derivative of 2x^2sin(x) ?
The derivative of 2x^2sin(x) is 2(2xsin(x)+cos(x)x^2)
What is the first derivative of 2x^2sin(x) ?
The first derivative of 2x^2sin(x) is 2(2xsin(x)+cos(x)x^2)