What is the integral from 1 to infinity of x/(1+x^2) ?

The integral from 1 to infinity of x/(1+x^2) is diverges

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integral from 1 to infinity of x/(1+x^2)

\int_{1}^{\infty} \frac{x}{1 + x ^{2}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{1 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{1 + x ^{2}} d x = \frac{1}{2} ln 1 + x^{2} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{1 + x ^{2}} d x =

diverges

= diverges

x \to 3 lim (\frac{1}{( 3 - x ) ^{2}})

t^{2} y^{^{'}} + t y = 3, y (1) = 4

\int_{0}^{1} x^{3} - x^{2} d x

x \to 0 + lim (\frac{x ^{2}}{x})

\frac{( t - t )}{t ^{\frac{1}{3}}}

What is the integral from 1 to infinity of x/(1+x^2) ?
The integral from 1 to infinity of x/(1+x^2) is diverges