What is the sum from n=2 to infinity of (ln(n))/n ?

The sum from n=2 to infinity of (ln(n))/n is diverges

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sum from n=2 to infinity of (ln(n))/n

n = 2 \sum \infty \frac{ln ( n )}{n}

diverges

Solution steps

n = 2 \sum \infty \frac{ln ( n )}{n}

Apply Series Integral Test:

diverges

= diverges

\int 7 sin (5 θ) sin (θ) d θ

a^{2}

\int x sin^{2} (2 x^{2}) cos^{2} (2 x^{2}) d x

\frac{x ^{2} + 1}{x ^{2} - 1}

y = x^{2} + 5, (4, 21)

What is the sum from n=2 to infinity of (ln(n))/n ?
The sum from n=2 to infinity of (ln(n))/n is diverges