What is the sum from n=0 to infinity of (2n-3)(4x)^n ?

The sum from n=0 to infinity of (2n-3)(4x)^n is Interval of convergence is-1/4 <x< 1/4

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sum from n=0 to infinity of (2n-3)(4x)^n

n = 0 \sum \infty (2 n - 3) (4 x)^{n}

Interval of convergence is - \frac{1}{4} < x < \frac{1}{4}

Solution steps

n = 0 \sum \infty (2 n - 3) (4 x)^{n}

Use the Ratio Test to compute the convergence interval

Interval of convergence is - \frac{1}{4} < x < \frac{1}{4}

f (t) = 1.7 e^{0.76 t}

\frac{d}{d x} ((1 - x^{2}))

\int \frac{( x - 1 ) ^{3}}{x} d x

f (x) = 3 x^{2} + 1

\frac{1}{2} x^{4}

What is the sum from n=0 to infinity of (2n-3)(4x)^n ?
The sum from n=0 to infinity of (2n-3)(4x)^n is Interval of convergence is-1/4 <x< 1/4