What is the integral of tsinh(mt) ?

The integral of tsinh(mt) is 1/m tcosh(mt)-1/(m^2)sinh(mt)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of tsinh(mt)

\int t sinh (m t) d t

\frac{1}{m} t cosh (m t) - \frac{1}{m ^{2}} sinh (m t) + C

Solution steps

\int t sinh (m t) d t

Apply Integration By Parts

: \frac{1}{m} t cosh (m t) - \int \frac{1}{m} cosh (m t) d t

= \frac{1}{m} t cosh (m t) - \int \frac{1}{m} cosh (m t) d t

\int \frac{1}{m} cosh (m t) d t = \frac{1}{m ^{2}} sinh (m t)

= \frac{1}{m} t cosh (m t) - \frac{1}{m ^{2}} sinh (m t)

Add a constant to the solution

= \frac{1}{m} t cosh (m t) - \frac{1}{m ^{2}} sinh (m t) + C

f (x) = \frac{3}{x + 1}, at x = - 2

\frac{d y}{d t} = - 0.4 y + 6.2 e^{- 0.73 t}

\int e^{x} (cos (x)) d x

x + 2, x^{2}

\int x \cdot 4 - x^{2} d x

What is the integral of tsinh(mt) ?
The integral of tsinh(mt) is 1/m tcosh(mt)-1/(m^2)sinh(mt)+C