What is the derivative of 2+sin(3x) ?

The derivative of 2+sin(3x) is 3cos(3x)

What is the first derivative of 2+sin(3x) ?

The first derivative of 2+sin(3x) is 3cos(3x)

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\frac{d}{d x} (2 + sin (3 x))

3 cos (3 x)

Solution steps

\frac{d}{d x} (2 + sin (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 0 + cos (3 x) \cdot 3

Simplify

= 3 cos (3 x)

\int sin (x^{2} + y^{2})

A^{^{'}}

\int 2 sin (2 x) cos (2 x) d x

\int \frac{( x - 1 )}{( x + 4 )} d x

\int \frac{3}{x ^{4}} d x

What is the derivative of 2+sin(3x) ?
The derivative of 2+sin(3x) is 3cos(3x)
What is the first derivative of 2+sin(3x) ?
The first derivative of 2+sin(3x) is 3cos(3x)