What is the derivative of 1/(2x-5) ?

The derivative of 1/(2x-5) is -2/((2x-5)^2)

What is the first derivative of 1/(2x-5) ?

The first derivative of 1/(2x-5) is -2/((2x-5)^2)

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\frac{d}{d x} (\frac{1}{2 x - 5})

- \frac{2}{( 2 x - 5 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x - 5})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x - 5)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 5 ) ^{2}} \frac{d}{d x} (2 x - 5)

= - \frac{1}{( 2 x - 5 ) ^{2}} \frac{d}{d x} (2 x - 5)

\frac{d}{d x} (2 x - 5) = 2

= - \frac{1}{( 2 x - 5 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x - 5 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x - 5 ) ^{2}}

= - \frac{2}{( 2 x - 5 ) ^{2}}

f (2) = 4 lo g_{6} (x)

\frac{d}{d x} (2^{x} + 3)

x y^{^{'}} + y (1 + ln (x y)) = 0

\int 8 x d x

\frac{d}{d x} (\frac{3 x ^{2} + 4 x - 2}{x})

What is the derivative of 1/(2x-5) ?
The derivative of 1/(2x-5) is -2/((2x-5)^2)
What is the first derivative of 1/(2x-5) ?
The first derivative of 1/(2x-5) is -2/((2x-5)^2)