What is the derivative of xy+8 ?

The derivative of xy+8 is x(dy)/(dx)+y

What is the first derivative of xy+8 ?

The first derivative of xy+8 is x(dy)/(dx)+y

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\frac{d}{d x} (x y + 8)

x \frac{d y}{d x} + y

Solution steps

\frac{d}{d x} (x y + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y) + \frac{d}{d x} (8)

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

\frac{d}{d x} (8) = 0

= y + x \frac{d y}{d x} + 0

Simplify

= x \frac{d y}{d x} + y

h \to 0 lim (4 h - h^{2})

\int \frac{9 - 162 x}{25 - 81 x ^{2}} d x

n = 0 \sum \infty (n + 1)!

x \to 0 + lim (3 ln (x) + \frac{5}{x})

x \to 0 lim (- \frac{1}{4 x})

What is the derivative of xy+8 ?
The derivative of xy+8 is x(dy)/(dx)+y
What is the first derivative of xy+8 ?
The first derivative of xy+8 is x(dy)/(dx)+y