What is the integral of 7/(x+3) ?

The integral of 7/(x+3) is 7ln|x+3|+C

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integral of 7/(x+3)

\int \frac{7}{x + 3} d x

7 ln ∣ x + 3 ∣ + C

Solution steps

\int \frac{7}{x + 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{x + 3} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 7 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 7 ln ∣ u ∣

Substitute back

u = x + 3

= 7 ln ∣ x + 3 ∣

Add a constant to the solution

= 7 ln ∣ x + 3 ∣ + C

\int (sin (x))^{5} cos (x) d x

f (x) = 14 x^{\frac{1}{7}}

\frac{d}{d x} (arccsc (- 9 x^{2}))

8 x e^{x}

(1, 1), (- 1, 2)