What is the integral of 0.06x-0.6-(7700)/(x^2) ?

The integral of 0.06x-0.6-(7700)/(x^2) is 0.03x^2-0.6x+(7700)/x+C

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integral of 0.06x-0.6-(7700)/(x^2)

\int 0.06 x - 0.6 - \frac{7700}{x ^{2}} d x

0.03 x^{2} - 0.6 x + \frac{7700}{x} + C

Solution steps

\int 0.06 x - 0.6 - \frac{7700}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.06 x d x - \int 0.6 d x - \int \frac{7700}{x ^{2}} d x

\int 0.06 x d x = 0.03 x^{2}

\int 0.6 d x = 0.6 x

\int \frac{7700}{x ^{2}} d x = - \frac{7700}{x}

= 0.03 x^{2} - 0.6 x - (- \frac{7700}{x})

Simplify

= 0.03 x^{2} - 0.6 x + \frac{7700}{x}

Add a constant to the solution

= 0.03 x^{2} - 0.6 x + \frac{7700}{x} + C

\int_{- 1}^{1} 1 2^{x} d x

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 1})

y^{^{''}} + (8) y = 0

h \to + 0 lim (\frac{( 2 ^{h} - 1 )}{h})

n = 0 \sum \infty 100

What is the integral of 0.06x-0.6-(7700)/(x^2) ?
The integral of 0.06x-0.6-(7700)/(x^2) is 0.03x^2-0.6x+(7700)/x+C