What is the first derivative of x^2+4 ?

The first derivative of x^2+4 is 2x

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derivative of x^2+4

derivative of

x^{2} + 4

2 x

Solution steps

\frac{d}{d x} (x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 2 x + 0

Simplify

= 2 x

y = (4 x + 3)^{10}

\frac{d}{d x} ((- 4 x^{2} + 9)^{2})

\int (\frac{x ^{4} - 6 x ^{3} - 7 x}{x}) d x

x = y^{2} - 2, x = y

\int \frac{7 t - 6}{t + 1} d t