What is the tangent of f(x)=6sec(x) ?

The tangent of f(x)=6sec(x) is y=6sec(a_{0})tan(a_{0})x+6sec(a_{0})-6sec(a_{0})tan(a_{0})a_{0}

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tangent of f(x)=6sec(x)

tangent of

f (x) = 6 sec (x)

y = 6 sec (a_{0}) tan (a_{0}) x + 6 sec (a_{0}) - 6 sec (a_{0}) tan (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 sec (a_{0}))

Find the slope of

f (x) = 6 sec (x) : \frac{df ( x )}{d x} = 6 sec (x) tan (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 sec (a_{0}) tan (a_{0})

Find the line with slope m=

6 sec (a_{0}) tan (a_{0})

and passing through

(a_{0}, 6 sec (a_{0})) : y = 6 sec (a_{0}) tan (a_{0}) x + 6 sec (a_{0}) - 6 sec (a_{0}) tan (a_{0}) a_{0}

y = 6 sec (a_{0}) tan (a_{0}) x + 6 sec (a_{0}) - 6 sec (a_{0}) tan (a_{0}) a_{0}

\frac{d}{d x} (\frac{ln ( x )}{x ^{4}})

\frac{d y}{d x} + y = e^{5 x}

3 y^{^{'}} - 9 x^{2} = 0

\frac{\partial}{\partial y} (e^{- 2 x} \cdot cos (2 y))

f (x) = \frac{1 - 2 x}{5 + x}

What is the tangent of f(x)=6sec(x) ?
The tangent of f(x)=6sec(x) is y=6sec(a_{0})tan(a_{0})x+6sec(a_{0})-6sec(a_{0})tan(a_{0})a_{0}