What is the sum from n=0 to infinity of 2/(n+1) ?

The sum from n=0 to infinity of 2/(n+1) is diverges

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sum from n=0 to infinity of 2/(n+1)

n = 0 \sum \infty \frac{2}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{2}{n + 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 0 \sum \infty \frac{1}{n + 1}

Apply Series Limit Comparison Test:

diverges

= 2 diverges

= diverges

arctan (x^{2} + x)

\int tan^{5} (4 x) sec^{3} (4 x) d x

x \to \infty + lim (x^{3})

\int - x y - y x^{2} + y^{2} d x

n = 1 \sum \infty \frac{4}{5 n}

What is the sum from n=0 to infinity of 2/(n+1) ?
The sum from n=0 to infinity of 2/(n+1) is diverges