What is laplacetransform f(t)=13e^{4t}*e^2 ?

The answer to laplacetransform f(t)=13e^{4t}*e^2 is (13e^2)/(s-4)

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laplacetransform f(t)=13e^{4t}*e^2

laplace transform

f (t) = 13 e^{4 t} \cdot e^{2}

\frac{13 e ^{2}}{s - 4}

Solution steps

L {13 e^{2} e^{4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 13 e^{2} L {e^{4 t}}

L {e^{4 t}} : \frac{1}{s - 4}

= 13 e^{2} \frac{1}{s - 4}

Refine

13 e^{2} \frac{1}{s - 4} : \frac{13 e ^{2}}{s - 4}

= \frac{13 e ^{2}}{s - 4}

\frac{d}{d x} (4 e^{- 6 x^{2}})

\int \frac{5 ( 1 - tan ^{2} ( x ) )}{sec ^{2} ( x )} d x

x - 4

\int \frac{25 x ^{2} + 4}{x ^{4}} d x

f (x) = ln (sin (2 x))

What is laplacetransform f(t)=13e^{4t}*e^2 ?
The answer to laplacetransform f(t)=13e^{4t}*e^2 is (13e^2)/(s-4)