What is the derivative of (7x^2+2)(6x+sqrt(x)) ?

The derivative of (7x^2+2)(6x+sqrt(x)) is 126x^2+14xsqrt(x)+(7x^{3/2})/2+1/(sqrt(x))+12

What is the first derivative of (7x^2+2)(6x+sqrt(x)) ?

The first derivative of (7x^2+2)(6x+sqrt(x)) is 126x^2+14xsqrt(x)+(7x^{3/2})/2+1/(sqrt(x))+12

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derivative of

(7 x^{2} + 2) (6 x + x)

126 x^{2} + 14 x x + \frac{7 x ^{\frac{3}{2}}}{2} + \frac{1}{x} + 12

Solution steps

\frac{d}{d x} ((7 x^{2} + 2) (6 x + x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 7 x^{2} + 2, g = 6 x + x

= \frac{d}{d x} (7 x^{2} + 2) (6 x + x) + \frac{d}{d x} (6 x + x) (7 x^{2} + 2)

\frac{d}{d x} (7 x^{2} + 2) = 14 x

\frac{d}{d x} (6 x + x) = 6 + \frac{1}{2 x}

= 14 x (6 x + x) + (6 + \frac{1}{2 x}) (7 x^{2} + 2)

Simplify

14 x (6 x + x) + (6 + \frac{1}{2 x}) (7 x^{2} + 2) : 126 x^{2} + 14 x x + \frac{7 x ^{\frac{3}{2}}}{2} + \frac{1}{x} + 12

= 126 x^{2} + 14 x x + \frac{7 x ^{\frac{3}{2}}}{2} + \frac{1}{x} + 12

y^{^{'}} = - 0.000631594 \cdot y

x \to 1 + lim (\frac{4 x - 1}{x - 1})

f (x) = 2 cos (x)

\int \frac{x ^{2}}{( 9 + x ^{2} ) ^{2}} d x

\frac{\partial}{\partial x} (\frac{25 x y}{x - y})

What is the derivative of (7x^2+2)(6x+sqrt(x)) ?
The derivative of (7x^2+2)(6x+sqrt(x)) is 126x^2+14xsqrt(x)+(7x^{3/2})/2+1/(sqrt(x))+12
What is the first derivative of (7x^2+2)(6x+sqrt(x)) ?
The first derivative of (7x^2+2)(6x+sqrt(x)) is 126x^2+14xsqrt(x)+(7x^{3/2})/2+1/(sqrt(x))+12