What is the solution for (dy}{dx}=\frac{-2x)/y ?

The solution for (dy}{dx}=\frac{-2x)/y is y=sqrt(-2x^2+c_{1)},y=-sqrt(-2x^2+c_{1)}

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(dy}{dx}=\frac{-2x)/y

\frac{d y}{d x} = \frac{- 2 x}{y}

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{- 2 x}{y}

Solve separable ODE:

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

y = - 2 x^{2} + c_{1}, y = - - 2 x^{2} + c_{1}

y = x + x

(x + y e^{(\frac{y}{x})}) d x - (x e^{\frac{y}{x}}) d y = 0

\frac{d y}{e ^{y}} = x d x

\int 6 x^{2} (x^{2} + 2) d x

x \to \infty lim (2 x + 1)

What is the solution for (dy}{dx}=\frac{-2x)/y ?
The solution for (dy}{dx}=\frac{-2x)/y is y=sqrt(-2x^2+c_{1)},y=-sqrt(-2x^2+c_{1)}