What is the derivative of 10x^2-5x+9 ?

The derivative of 10x^2-5x+9 is 20x-5

What is the first derivative of 10x^2-5x+9 ?

The first derivative of 10x^2-5x+9 is 20x-5

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\frac{d}{d x} (10 x^{2} - 5 x + 9)

20 x - 5

Solution steps

\frac{d}{d x} (10 x^{2} - 5 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (9)

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (9) = 0

= 20 x - 5 + 0

Simplify

= 20 x - 5

\int (e^{x} + 1)^{3} d x

\int (3 x^{2} - 6 x + \frac{9}{x} + 4 e^{x}) d x

y^{^{'}} = 0.05 y - 12 \cdot 4000

\frac{d}{d x} (x sin (x + y) + y cos (x))

\frac{d}{d t} (\frac{t}{1 + t ^{2}})

What is the derivative of 10x^2-5x+9 ?
The derivative of 10x^2-5x+9 is 20x-5
What is the first derivative of 10x^2-5x+9 ?
The first derivative of 10x^2-5x+9 is 20x-5