What is the integral of 1/(sqrt(5x+8)) ?

The integral of 1/(sqrt(5x+8)) is 2/5 sqrt(5x+8)+C

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integral of 1/(sqrt(5x+8))

\int \frac{1}{5 x + 8} d x

\frac{2}{5} 5 x + 8 + C

Solution steps

\int \frac{1}{5 x + 8} d x

Apply u-substitution

: \int \frac{1}{5 u} d u

= \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{5} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 5 x + 8

= \frac{1}{5} \cdot 2 (5 x + 8)^{\frac{1}{2}}

Simplify

\frac{1}{5} \cdot 2 (5 x + 8)^{\frac{1}{2}} : \frac{2}{5} 5 x + 8

= \frac{2}{5} 5 x + 8

Add a constant to the solution

= \frac{2}{5} 5 x + 8 + C

\frac{2}{( s ) ( s + 2 )}

\int x^{2} - 25 d x

\frac{d}{d x} (sin^{2} (2 x + 1))

\frac{d}{d x} ((2 x - 1)^{2})

x y^{^{'}} - y = \frac{4}{3} x ln (x)

What is the integral of 1/(sqrt(5x+8)) ?
The integral of 1/(sqrt(5x+8)) is 2/5 sqrt(5x+8)+C