What is the solution for (dx)/(dt)+2tx=t,x(0)= 3/2 ?

The solution for (dx)/(dt)+2tx=t,x(0)= 3/2 is x=e^{-t^2}+1/2

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(dx)/(dt)+2tx=t,x(0)= 3/2

\frac{d x}{d t} + 2 t x = t, x (0) = \frac{3}{2}

x = e^{- t^{2}} + \frac{1}{2}

Solution steps

\frac{d x}{d t} + 2 t x = t

Solve separable ODE:

x = e^{- t^{2}} + \frac{1}{2}

x = e^{- t^{2}} + \frac{1}{2}

f (x) = 5 x^{3} + 4 x, at x = - 3

f (x) = x \cdot cos (x)

\frac{d}{d x} (((x^{2} + 3)^{5} + x)^{2})

\frac{e ^{x}}{8 + e ^{x}}

\frac{d}{d x} (x + \frac{9}{x})

What is the solution for (dx)/(dt)+2tx=t,x(0)= 3/2 ?
The solution for (dx)/(dt)+2tx=t,x(0)= 3/2 is x=e^{-t^2}+1/2