What is the limit as x approaches 2 of (x^3+7x+6)/(x^3+x^2-4x-4) ?

The limit as x approaches 2 of (x^3+7x+6)/(x^3+x^2-4x-4) is diverges

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limit as x approaches 2 of (x^3+7x+6)/(x^3+x^2-4x-4)

x \to 2 lim (\frac{x ^{3} + 7 x + 6}{x ^{3} + x ^{2} - 4 x - 4})

diverges

Solution steps

x \to 2 lim (\frac{x ^{3} + 7 x + 6}{x ^{3} + x ^{2} - 4 x - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x ^{3} + 7 x + 6}{x ^{3} + x ^{2} - 4 x - 4}) = \infty

x \to 2 - lim (\frac{x ^{3} + 7 x + 6}{x ^{3} + x ^{2} - 4 x - 4}) = - \infty

= diverges

\int \frac{1}{2 ^{2} + 3 x ^{2}} d x

f (x) = 2 x^{3} - 24 x^{2} + 97 x + 7

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x - 2})

x \to 10 lim (e^{- x})

\frac{d ^{2}}{d x ^{2}} (5 (x^{2} + 1)^{4})

What is the limit as x approaches 2 of (x^3+7x+6)/(x^3+x^2-4x-4) ?
The limit as x approaches 2 of (x^3+7x+6)/(x^3+x^2-4x-4) is diverges