What is the sum from n=1 to infinity of (2n)/(1+n^4) ?

The sum from n=1 to infinity of (2n)/(1+n^4) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (2n)/(1+n^4)

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}

converges

Solution steps

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{1 + n ^{4}}

Apply Series Comparison Test:

converges

= 2 converges

= converges

\frac{\partial}{\partial x} (k v (1 - e^{(- \frac{t}{k})}))

\int_{0}^{3} x d x

x^{3} y^{^{'}} + 2 x^{2} y = 2 cos (3 x) y^{- \frac{1}{2}}

x \to \infty lim (\frac{2 x ^{2} - 9 x - 2}{- 5 x ^{2} - 10 x + 3})

\frac{d}{d x} ((x^{2} + y^{2}))

What is the sum from n=1 to infinity of (2n)/(1+n^4) ?
The sum from n=1 to infinity of (2n)/(1+n^4) is converges